What is expand ((x-4)(x-3)^2)/((x+1)(x-2)^3) ?

The solution to expand ((x-4)(x-3)^2)/((x+1)(x-2)^3) is (x^3-10x^2+33x-36)/(x^4-5x^3+6x^2+4x-8)

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expand ((x-4)(x-3)^2)/((x+1)(x-2)^3)

expand

\frac{( x - 4 ) ( x - 3 ) ^{2}}{( x + 1 ) ( x - 2 ) ^{3}}

\frac{x ^{3} - 10 x ^{2} + 33 x - 36}{x ^{4} - 5 x ^{3} + 6 x ^{2} + 4 x - 8}

Solution steps

\frac{( x - 4 ) ( x - 3 ) ^{2}}{( x + 1 ) ( x - 2 ) ^{3}}

(x - 2)^{3} = x^{3} - 6 x^{2} + 12 x - 8

= \frac{( x - 4 ) ( x - 3 ) ^{2}}{( x + 1 ) ( x ^{3} - 6 x ^{2} + 12 x - 8 )}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{( x - 4 ) ( x ^{2} - 6 x + 9 )}{( x + 1 ) ( x ^{3} - 6 x ^{2} + 12 x - 8 )}

Expand

(x + 1) (x^{3} - 6 x^{2} + 12 x - 8) : x^{4} - 5 x^{3} + 6 x^{2} + 4 x - 8

= \frac{( x - 4 ) ( x ^{2} - 6 x + 9 )}{x ^{4} - 5 x ^{3} + 6 x ^{2} + 4 x - 8}

Expand

(x - 4) (x^{2} - 6 x + 9) : x^{3} - 10 x^{2} + 33 x - 36

= \frac{x ^{3} - 10 x ^{2} + 33 x - 36}{x ^{4} - 5 x ^{3} + 6 x ^{2} + 4 x - 8}

(\frac{3}{5} x + \frac{3}{11} y)^{2}

\frac{( 46 - x ) ( 33 - x )}{( 39 - x ) ^{2}}

\frac{1}{s ( s ^{2} + 2 s + 4 )}

\frac{s ^{2} + s + 1 - e ^{- π s}}{s ( s ^{2} + 4 )}

\frac{2 x ( 1 - y x + y ^{2} )}{x ^{2} - y ^{2}}

What is expand ((x-4)(x-3)^2)/((x+1)(x-2)^3) ?
The solution to expand ((x-4)(x-3)^2)/((x+1)(x-2)^3) is (x^3-10x^2+33x-36)/(x^4-5x^3+6x^2+4x-8)