What is expand (2i+1)^3-(2j+1)^3 ?

The solution to expand (2i+1)^3-(2j+1)^3 is (-8j^3-12j^2-6j-12)-2i

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expand (2i+1)^3-(2j+1)^3

expand

(2 i + 1)^{3} - (2 j + 1)^{3}

(- 8 j^{3} - 12 j^{2} - 6 j - 12) - 2 i

Solution steps

(2 i + 1)^{3} - (2 j + 1)^{3}

Expand

(2 i + 1)^{3} : - 2 i - 11

= - 2 i - 11 - (2 j + 1)^{3}

Expand

- (2 j + 1)^{3} : - 8 j^{3} - 12 j^{2} - 6 j - 1

= - 2 i - 11 - 8 j^{3} - 12 j^{2} - 6 j - 1

Simplify

- 2 i - 11 - 8 j^{3} - 12 j^{2} - 6 j - 1 : - 2 i - 8 j^{3} - 12 j^{2} - 6 j - 12

= - 2 i - 8 j^{3} - 12 j^{2} - 6 j - 12

Rewrite in standard complex form:

(- 8 j^{3} - 12 j^{2} - 6 j - 12) - 2 i

= (- 8 j^{3} - 12 j^{2} - 6 j - 12) - 2 i

4 x - 2 (x - 2 = - 9 + 4 x + 7)

3 y^{2} (1 - x)^{3} + e^{- x}

A (6, - 8) y B (- 5, 0)

\frac{29000 ( - x ^{2} + 90 )}{( x ^{2} + 90 ) ^{2}}

\frac{( x - 3 ) ^{2}}{x - 3}

What is expand (2i+1)^3-(2j+1)^3 ?
The solution to expand (2i+1)^3-(2j+1)^3 is (-8j^3-12j^2-6j-12)-2i