What is the d/(dq)((c)(0.2q^2+2q+500)) ?

The d/(dq)((c)(0.2q^2+2q+500)) is c(0.4q+2)

What is the first d/(dq)((c)(0.2q^2+2q+500)) ?

The first d/(dq)((c)(0.2q^2+2q+500)) is c(0.4q+2)

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\frac{d}{d q} ((c) (0.2 q^{2} + 2 q + 500))

c (0.4 q + 2)

Solution steps

\frac{d}{d q} ((c) (0.2 q^{2} + 2 q + 500))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d q} (0.2 q^{2} + 2 q + 500)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= c (\frac{d}{d q} (0.2 q^{2}) + \frac{d}{d q} (2 q) + \frac{d}{d q} (500))

\frac{d}{d q} (0.2 q^{2}) = 0.4 q

\frac{d}{d q} (2 q) = 2

\frac{d}{d q} (500) = 0

= c (0.4 q + 2 + 0)

Simplify

= c (0.4 q + 2)

(y = 2 - x) (0.5)

(- 4, - 5) y (6, - 1)

\frac{- 7 x ^{8} + 9}{( x ^{8} + 9 ) ^{2}}

a (e + 2 d)^{3} + b (e + 2 d)^{3} + c

(e + c + f)^{2}

What is the d/(dq)((c)(0.2q^2+2q+500)) ?
The d/(dq)((c)(0.2q^2+2q+500)) is c(0.4q+2)
What is the first d/(dq)((c)(0.2q^2+2q+500)) ?
The first d/(dq)((c)(0.2q^2+2q+500)) is c(0.4q+2)