What is expand ((x-2)(x-3))/6 ?

The solution to expand ((x-2)(x-3))/6 is (x^2)/6-(5x)/6+1

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expand ((x-2)(x-3))/6

expand

\frac{( x - 2 ) ( x - 3 )}{6}

\frac{x ^{2}}{6} - \frac{5 x}{6} + 1

Solution steps

\frac{( x - 2 ) ( x - 3 )}{6}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{x ^{2} - 5 x + 6}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 5 x + 6}{6} = \frac{x ^{2}}{6} - \frac{5 x}{6} + \frac{6}{6}

= \frac{x ^{2}}{6} - \frac{5 x}{6} + \frac{6}{6}

Apply rule

\frac{a}{a} = 1

\frac{6}{6} = 1

= \frac{x ^{2}}{6} - \frac{5 x}{6} + 1

(x + 1) (x^{2} + \frac{1}{5})

\frac{3}{4} - \frac{2}{5} + \frac{3}{7}

(e^{- x} + e^{2 x})^{2}

\frac{( x - 2 )}{3 ( x + 2 )}

- \frac{6}{( 3 - 1 ) ^{4}} + cos (3 - 1)

What is expand ((x-2)(x-3))/6 ?
The solution to expand ((x-2)(x-3))/6 is (x^2)/6-(5x)/6+1