What are the solutions to the equation -20w-25=4w^2 ?

The solutions to the equation -20w-25=4w^2 are w=-5/2

Find the zeros of -20w-25=4w^2

The zeros of -20w-25=4w^2 are w=-5/2

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- 20 w - 25 = 4 w^{2}

w = - \frac{5}{2}

Decimal Notation

w = - 2.5

Solution steps

- 20 w - 25 = 4 w^{2}

Switch sides

4 w^{2} = - 20 w - 25

Move

25

to the left side

4 w^{2} + 25 = - 20 w

Move

20 w

to the left side

4 w^{2} + 25 + 20 w = 0

Write in the standard form

a x^{2} + b x + c = 0

4 w^{2} + 20 w + 25 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

w_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

w = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

w = - \frac{5}{2}

The solution to the quadratic equation is:

w = - \frac{5}{2}

∣ 9 x - 72 ∣ = 0

\frac{16}{3} - 3

\frac{1}{\frac{8}{17}}

- 2 = \frac{3 x + 7}{4}

6 x - 9 = 2 x + 7

What are the solutions to the equation -20w-25=4w^2 ?
The solutions to the equation -20w-25=4w^2 are w=-5/2
Find the zeros of -20w-25=4w^2
The zeros of -20w-25=4w^2 are w=-5/2