What is expand (x^2+6)/(2x+1)-1/2 x ?

The solution to expand (x^2+6)/(2x+1)-1/2 x is (-x+12)/(4x+2)

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expand (x^2+6)/(2x+1)-1/2 x

expand

\frac{x ^{2} + 6}{2 x + 1} - \frac{1}{2} x

\frac{- x + 12}{4 x + 2}

Solution steps

\frac{x ^{2} + 6}{2 x + 1} - \frac{1}{2} x

\frac{1}{2} x = \frac{x}{2}

= \frac{x ^{2} + 6}{2 x + 1} - \frac{x}{2}

Least Common Multiplier of

2 x + 1, 2 : 2 (2 x + 1)

Adjust Fractions based on the LCM

= \frac{( x ^{2} + 6 ) \cdot 2}{( 2 x + 1 ) \cdot 2} - \frac{x ( 2 x + 1 )}{2 ( 2 x + 1 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( x ^{2} + 6 ) \cdot 2 - x ( 2 x + 1 )}{2 ( 2 x + 1 )}

Expand

2 (2 x + 1) : 4 x + 2

= \frac{2 ( x ^{2} + 6 ) - x ( 2 x + 1 )}{4 x + 2}

Expand

(x^{2} + 6) \cdot 2 - x (2 x + 1) : - x + 12

= \frac{- x + 12}{4 x + 2}

12 (1 - \frac{0.87}{π})

(x - 1 - 1) (x - 1 + 1)

3 (x + 2)

8 (8 t - 4 sin (π t))

\frac{\partial}{\partial x} ((z) (x^{2} + y^{3}))

What is expand (x^2+6)/(2x+1)-1/2 x ?
The solution to expand (x^2+6)/(2x+1)-1/2 x is (-x+12)/(4x+2)