What is (\partial)/(\partial x)((x)(x-3)(y-4)) ?

The answer to (\partial)/(\partial x)((x)(x-3)(y-4)) is (y-4)(2x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((x)(x-3)(y-4))

\frac{\partial}{\partial x} ((x) (x - 3) (y - 4))

(y - 4) (2 x - 3)

Solution steps

\frac{\partial}{\partial x} ((x) (x - 3) (y - 4))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y - 4) \frac{\partial}{\partial x} (x (x - 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x - 3

= (y - 4) (\frac{\partial}{\partial x} (x) (x - 3) + \frac{\partial}{\partial x} (x - 3) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x - 3) = 1

= (y - 4) (1 \cdot (x - 3) + 1 \cdot x)

Simplify

(y - 4) (1 \cdot (x - 3) + 1 \cdot x) : (y - 4) (2 x - 3)

= (y - 4) (2 x - 3)

f (x) x (2 (y)^{''} - x (y)^{'} = e^{- x})

e^{x} (x + e^{x})

\frac{x ( 2 - x ) ^{4}}{4}

(x + sin (x) - 1)^{2}

(2 x) (3 x + 1 + 1)

What is (\partial)/(\partial x)((x)(x-3)(y-4)) ?
The answer to (\partial)/(\partial x)((x)(x-3)(y-4)) is (y-4)(2x-3)