What are the solutions to the equation 3x^2+249=-54x ?

The solutions to the equation 3x^2+249=-54x are x=-9+sqrt(2)i,x=-9-sqrt(2)i

Find the zeros of 3x^2+249=-54x

The zeros of 3x^2+249=-54x are x=-9+sqrt(2)i,x=-9-sqrt(2)i

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3 x^{2} + 249 = - 54 x

x = - 9 + 2 i, x = - 9 - 2 i

Solution steps

3 x^{2} + 249 = - 54 x

Move

54 x

to the left side

3 x^{2} + 249 + 54 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 54 x + 249 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 \cdot 3 \cdot 249}{2 \cdot 3}

Simplify

5 4^{2} - 4 \cdot 3 \cdot 249 : 62 i

x_{1, 2} = \frac{- 54 \pm 6 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 54 + 6 2 i}{2 \cdot 3}, x_{2} = \frac{- 54 - 6 2 i}{2 \cdot 3}

x = \frac{- 54 + 6 2 i}{2 \cdot 3} : - 9 + 2 i

x = \frac{- 54 - 6 2 i}{2 \cdot 3} : - 9 - 2 i

The solutions to the quadratic equation are:

x = - 9 + 2 i, x = - 9 - 2 i

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What are the solutions to the equation 3x^2+249=-54x ?
The solutions to the equation 3x^2+249=-54x are x=-9+sqrt(2)i,x=-9-sqrt(2)i
Find the zeros of 3x^2+249=-54x
The zeros of 3x^2+249=-54x are x=-9+sqrt(2)i,x=-9-sqrt(2)i