What is expand (ln(y-2)+(x-3)/(y-2)=C)y-2 ?

The solution to expand (ln(y-2)+(x-3)/(y-2)=C)y-2 is yln(y-2)+(yx-3y)/(y-2)=C-2

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expand (ln(y-2)+(x-3)/(y-2)=C)y-2

expand

(ln (y - 2) + \frac{x - 3}{y - 2} = C) y - 2

y ln (y - 2) + \frac{y x - 3 y}{y - 2} = C - 2

Solution steps

(ln (y - 2) + \frac{x - 3}{y - 2} = C) y - 2

= y (ln (y - 2) + = C \frac{x - 3}{y - 2}) - 2

Expand

y (ln (y - 2) + \frac{x - 3}{y - 2} = C) : y ln (y - 2) + \frac{y x - 3 y}{y - 2} = C

y ln (y - 2) + \frac{y x - 3 y}{y - 2} = C - 2

\frac{d ^{2}}{d x ^{2}} ((y) (4 x^{3} - 7 x^{2} + 3 x - 9))

(6, - 8, 3) y (- 4, - 1, - 3)

\frac{0.8 ( 1.5 P + 1.5 T )}{P}

(x + 2 + 3 x - 6)^{2}

(z + \frac{1}{2}) \cdot (z - 1)

What is expand (ln(y-2)+(x-3)/(y-2)=C)y-2 ?
The solution to expand (ln(y-2)+(x-3)/(y-2)=C)y-2 is yln(y-2)+(yx-3y)/(y-2)=C-2