What is expand (4s-10)/((s-3)(s-2)(s-1)) ?

The solution to expand (4s-10)/((s-3)(s-2)(s-1)) is (4s-10)/(s^3-6s^2+11s-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4s-10)/((s-3)(s-2)(s-1))

expand

\frac{4 s - 10}{( s - 3 ) ( s - 2 ) ( s - 1 )}

\frac{4 s - 10}{s ^{3} - 6 s ^{2} + 11 s - 6}

Solution steps

\frac{4 s - 10}{( s - 3 ) ( s - 2 ) ( s - 1 )}

Expand

(s - 3) (s - 2) (s - 1) : s^{3} - 6 s^{2} + 11 s - 6

= \frac{4 s - 10}{s ^{3} - 6 s ^{2} + 11 s - 6}

P (x, y) A (- 5, - 4) B (3, 18)

- 9 (x + Δ x)^{2} - 15

sec^{2} (θ) (1 + cos (θ))

(x - 3) (x^{2} - 4 x + 3 x - 43)

3 (5 - 2)

What is expand (4s-10)/((s-3)(s-2)(s-1)) ?
The solution to expand (4s-10)/((s-3)(s-2)(s-1)) is (4s-10)/(s^3-6s^2+11s-6)