What is expand (4cos(t)-sin(t))^2 ?

The solution to expand (4cos(t)-sin(t))^2 is 16cos^2(t)-8cos(t)sin(t)+sin^2(t)

Popular >

expand (4cos(t)-sin(t))^2

expand

(4 cos (t) - sin (t))^{2}

16 cos^{2} (t) - 8 cos (t) sin (t) + sin^{2} (t)

Solution steps

(4 cos (t) - sin (t))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(4 cos (t) - sin (t))^{2} = (4 cos (t))^{2} - 2 \cdot 4 cos (t) sin (t) + sin^{2} (t)

= (4 cos (t))^{2} - 2 \cdot 4 cos (t) sin (t) + sin^{2} (t)

Simplify

(4 cos (t))^{2} - 2 \cdot 4 cos (t) sin (t) + sin^{2} (t) : 16 cos^{2} (t) - 8 cos (t) sin (t) + sin^{2} (t)

= 16 cos^{2} (t) - 8 cos (t) sin (t) + sin^{2} (t)

sin ((2 n + 1) π)

\frac{x ( x - 1 )}{( 15 + x ) ( 14 + x )}

(x - \frac{1}{2}) \cdot (x + \frac{1}{2})

\frac{2}{( s + 1 ) \cdot ( s ^{2} + 2 s + 2 ) \cdot ( s ^{3} + 3 s ^{2} + 4 s + 4 )}

(x + 4 i)^{3} (x - 4 i)

What is expand (4cos(t)-sin(t))^2 ?
The solution to expand (4cos(t)-sin(t))^2 is 16cos^2(t)-8cos(t)sin(t)+sin^2(t)