What is expand 3((x+4)(x+2)(x+1)(x-4)) ?

The solution to expand 3((x+4)(x+2)(x+1)(x-4)) is 3x^4+9x^3-42x^2-144x-96

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3((x+4)(x+2)(x+1)(x-4))

expand

3 ((x + 4) (x + 2) (x + 1) (x - 4))

3 x^{4} + 9 x^{3} - 42 x^{2} - 144 x - 96

Solution steps

3 ((x + 4) (x + 2) (x + 1) (x - 4))

Remove parentheses:

(a) = a

= 3 (x + 4) (x + 2) (x + 1) (x - 4)

Expand

(x + 4) (x + 2) : x^{2} + 6 x + 8

= 3 (x^{2} + 6 x + 8) (x + 1) (x - 4)

Expand

(x^{2} + 6 x + 8) (x + 1) : x^{3} + 7 x^{2} + 14 x + 8

= 3 (x^{3} + 7 x^{2} + 14 x + 8) (x - 4)

Expand

(x^{3} + 7 x^{2} + 14 x + 8) (x - 4) : x^{4} + 3 x^{3} - 14 x^{2} - 48 x - 32

= 3 (x^{4} + 3 x^{3} - 14 x^{2} - 48 x - 32)

Expand

3 (x^{4} + 3 x^{3} - 14 x^{2} - 48 x - 32) : 3 x^{4} + 9 x^{3} - 42 x^{2} - 144 x - 96

= 3 x^{4} + 9 x^{3} - 42 x^{2} - 144 x - 96

\frac{( x - 1 ) ( x + 5 )}{x - 4}

(m - 7 + 7) (m - 7 - 7)

- 2 sin (t) (16 - 2 sin (t))

\frac{( x - y )}{( x + y ) ^{3}}

\frac{- x ^{2} + 18 x - 49}{( x ^{2} - 49 ) ^{2}}

What is expand 3((x+4)(x+2)(x+1)(x-4)) ?
The solution to expand 3((x+4)(x+2)(x+1)(x-4)) is 3x^4+9x^3-42x^2-144x-96