What is expand 1/(s(s+1)(s^2+6s+13)) ?

The solution to expand 1/(s(s+1)(s^2+6s+13)) is 1/(s^4+7s^3+19s^2+13s)

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expand 1/(s(s+1)(s^2+6s+13))

expand

\frac{1}{s ( s + 1 ) ( s ^{2} + 6 s + 13 )}

\frac{1}{s ^{4} + 7 s ^{3} + 19 s ^{2} + 13 s}

Solution steps

\frac{1}{s ( s + 1 ) ( s ^{2} + 6 s + 13 )}

Expand

s (s + 1) (s^{2} + 6 s + 13) : s^{4} + 7 s^{3} + 19 s^{2} + 13 s

= \frac{1}{s ^{4} + 7 s ^{3} + 19 s ^{2} + 13 s}

\frac{x x ^{2} + 36 \cdot 3 - 2 ( x ^{2} + 36 )}{6 ( x ^{2} + 36 )}

ln (4) m^{3} n^{5}

\frac{( x ^{2} - 2 x + 1 )}{x ^{2} ( 2 x ^{2} + 1 )}

\frac{u ^{5} ( u ^{3} + 1 )}{u ^{2} + 1}

- \frac{1 ( 3 + 6 - 8 + 3 )}{- 1 ( 3 + 6 - 8 + 3 )}

What is expand 1/(s(s+1)(s^2+6s+13)) ?
The solution to expand 1/(s(s+1)(s^2+6s+13)) is 1/(s^4+7s^3+19s^2+13s)