What is expand-(4(x+4)^2)/9 ?

The solution to expand-(4(x+4)^2)/9 is -(4x^2)/9-(32x)/9-64/9

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expand-(4(x+4)^2)/9

expand

- \frac{4 ( x + 4 ) ^{2}}{9}

- \frac{4 x ^{2}}{9} - \frac{32 x}{9} - \frac{64}{9}

Solution steps

- \frac{4 ( x + 4 ) ^{2}}{9}

(x + 4)^{2} = x^{2} + 8 x + 16

= - \frac{4 ( x ^{2} + 8 x + 16 )}{9}

Expand

4 (x^{2} + 8 x + 16) : 4 x^{2} + 32 x + 64

= - \frac{4 x ^{2} + 32 x + 64}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} + 32 x + 64}{9} = - (\frac{4 x ^{2}}{9}) - (\frac{32 x}{9}) - (\frac{64}{9})

= - (\frac{4 x ^{2}}{9}) - (\frac{32 x}{9}) - (\frac{64}{9})

Remove parentheses:

(a) = a

= - \frac{4 x ^{2}}{9} - \frac{32 x}{9} - \frac{64}{9}

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(x + \frac{( m - l - t )}{2})^{2}

What is expand-(4(x+4)^2)/9 ?
The solution to expand-(4(x+4)^2)/9 is -(4x^2)/9-(32x)/9-64/9