What is expand (k(k-1)(k+1))/3 ?

The solution to expand (k(k-1)(k+1))/3 is (k^3)/3-k/3

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expand (k(k-1)(k+1))/3

expand

\frac{k ( k - 1 ) ( k + 1 )}{3}

\frac{k ^{3}}{3} - \frac{k}{3}

Solution steps

\frac{k ( k - 1 ) ( k + 1 )}{3}

Expand

k (k - 1) (k + 1) : k^{3} - k

= \frac{k ^{3} - k}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{k ^{3} - k}{3} = \frac{k ^{3}}{3} - \frac{k}{3}

= \frac{k ^{3}}{3} - \frac{k}{3}

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What is expand (k(k-1)(k+1))/3 ?
The solution to expand (k(k-1)(k+1))/3 is (k^3)/3-k/3