What is expand-(21x)/(128)+21/256-x/(32)+1/32 ?

The solution to expand-(21x)/(128)+21/256-x/(32)+1/32 is -(25x)/(128)+1/32+21/256

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expand-(21x)/(128)+21/256-x/(32)+1/32

expand

- \frac{21 x}{128} + \frac{21}{256} - \frac{x}{32} + \frac{1}{32}

- \frac{25 x}{128} + \frac{1}{32} + \frac{21}{256}

Solution steps

- \frac{21 x}{128} + \frac{21}{256} - \frac{x}{32} + \frac{1}{32}

Group like terms

= - \frac{21 x}{128} - \frac{x}{32} + \frac{1}{32} + \frac{21}{256}

Combine the fractions

- \frac{x}{32} + \frac{1}{32} : \frac{- x + 1}{32}

= - \frac{21 x}{128} + \frac{- x + 1}{32} + \frac{21}{256}

Combine the fractions

- \frac{21 x}{128} + \frac{- x + 1}{32} : \frac{- 25 x + 4}{128}

= \frac{21}{256} + \frac{- 25 x + 4}{128}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 25 x + 4}{128} = - \frac{25 x}{128} + \frac{4}{128}

= \frac{21}{256} - \frac{25 x}{128} + \frac{4}{128}

Group like terms

= - \frac{25 x}{128} + \frac{4}{128} + \frac{21}{256}

Cancel

\frac{4}{128} : \frac{1}{32}

= - \frac{25 x}{128} + \frac{1}{32} + \frac{21}{256}

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What is expand-(21x)/(128)+21/256-x/(32)+1/32 ?
The solution to expand-(21x)/(128)+21/256-x/(32)+1/32 is -(25x)/(128)+1/32+21/256