What is expand sin(t)u(t-pi) ?

The solution to expand sin(t)u(t-pi) is tusin(t)-piusin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand sin(t)u(t-pi)

expand

sin (t) u (t - π)

t u sin (t) - π u sin (t)

Solution steps

sin (t) u (t - π)

= u sin (t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) u, b = t, c = π

= sin (t) u t - sin (t) u π

= t u sin (t) - π u sin (t)

2 (x + 1^{2} = 32)

(6 x^{2} - 5 x y - 2 y^{2}) d x - (6 x^{2} - 8 x y - y^{2}) d y

\frac{x t}{( 3 x ^{2} + 2 ) ( 9 t ^{2} x ^{4} + 12 t ^{2} x ^{2} + 4 t ^{2} + 6 )}

((4 x + 2) - 4 x) \cdot ((4 x + 2) + 4 x)

2 (ln (x + 3) + 1)

What is expand sin(t)u(t-pi) ?
The solution to expand sin(t)u(t-pi) is tusin(t)-piusin(t)