What is expand d/(d(1))(x^{2/3}-y^{2/3}-y=1) ?

The solution to expand d/(d(1))(x^{2/3}-y^{2/3}-y=1) is x^{2/3}-y^{2/3}-y=1

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expand d/(d(1))(x^{2/3}-y^{2/3}-y=1)

expand

\frac{d}{d ( 1 )} (x^{\frac{2}{3}} - y^{\frac{2}{3}} - y = 1)

x^{\frac{2}{3}} - y^{\frac{2}{3}} - y = 1

Solution steps

\frac{d}{d ( 1 )} (x^{\frac{2}{3}} - y^{\frac{2}{3}} - y = 1)

= \frac{d}{( 1 ) d} (x^{\frac{2}{3}} - y^{\frac{2}{3}} - 1 = y)

Distribute parentheses

= \frac{d}{d ( 1 )} x^{\frac{2}{3}} + \frac{d}{d ( 1 )} (- y^{\frac{2}{3}}) + \frac{d}{d ( 1 )} (- y = 1)

Apply minus-plus rules

+ (- a) = - a

\frac{d}{( 1 ) d} x^{\frac{2}{3}} - \frac{d}{( 1 ) d} y^{\frac{2}{3}} - \frac{d}{( 1 ) d} y = 1

Expand

\frac{d}{( 1 ) d} x^{\frac{2}{3}} - \frac{d}{( 1 ) d} y^{\frac{2}{3}} - \frac{d}{( 1 ) d} y : x^{\frac{2}{3}} - y^{\frac{2}{3}} - y

x^{\frac{2}{3}} - y^{\frac{2}{3}} - y = 1

(5 x^{3} - 2 x^{2}) (6 x^{3})^{'}

(\frac{0.3 + x}{2} + 0.8) (90 + 300 x)

(2 x - 2) (2 x + 2)

((2)^{2})^{3}

\frac{11 x ^{2} - 26 x - 61}{( x ^{2} - 8 x + 15 ) ^{2}}

What is expand d/(d(1))(x^{2/3}-y^{2/3}-y=1) ?
The solution to expand d/(d(1))(x^{2/3}-y^{2/3}-y=1) is x^{2/3}-y^{2/3}-y=1