What is expand (x-3)(\times+3) ?

The solution to expand (x-3)(\times+3) is 3x-9

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expand (x-3)(\times+3)

expand

(x - 3) (\cdot + 3)

3 x - 9

Solution steps

(x - 3) (3)

= (3) (x - 3)

Apply the distributive law:

a (b - c) = ab - a c

a = (3), b = x, c = 3

= (3) x - (3) \cdot 3

Simplify

(3) x - (3) \cdot 3 : 3 x - 9

= 3 x - 9

\frac{( 2 x + 1 ) ^{2}}{x + 1}

ro t a c i o na l (x, - y)

(9 X - 13 X^{3} + 12 - 15 X^{2}) \cdot (- 2 X^{3})^{'}

64 e^{8 x} (x - 2)^{3} (2 x - 3)

\frac{( 2 ^{k + 1} )}{( k + 1 ) !}