What is expand-(-cos(θ)-λ)(1/2 sin^2(θ)) ?

The solution to expand-(-cos(θ)-λ)(1/2 sin^2(θ)) is (sin^2(θ)cos(θ)+sin^2(θ)λ)/2

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expand-(-cos(θ)-λ)(1/2 sin^2(θ))

expand

- (- cos (θ) - λ) (\frac{1}{2} sin^{2} (θ))

\frac{sin ^{2} ( θ ) cos ( θ ) + sin ^{2} ( θ ) λ}{2}

Solution steps

- (- cos (θ) - λ) (\frac{1}{2} sin^{2} (θ))

= - (\frac{1}{2} sin^{2} (θ)) (- cos (θ) - λ)

Apply the distributive law:

a (b - c) = ab - a c

- (\frac{1}{2} sin^{2} (θ)) (- cos (θ) - λ) = - \frac{1}{2} sin^{2} (θ) (- cos (θ)) - (- \frac{1}{2} sin^{2} (θ)) λ

= - \frac{1}{2} sin^{2} (θ) (- cos (θ)) - (- \frac{1}{2} sin^{2} (θ)) λ

Simplify

- \frac{1}{2} sin^{2} (θ) (- cos (θ)) - (- \frac{1}{2} sin^{2} (θ)) λ : \frac{sin ^{2} ( θ ) cos ( θ ) + sin ^{2} ( θ ) λ}{2}

= \frac{sin ^{2} ( θ ) cos ( θ ) + sin ^{2} ( θ ) λ}{2}

a sin (x) - cos (x) - a cos (x) (3 sin (x) + 4 cos (x))

- 2 (93 + 5113)

\frac{( x - y ) ^{2}}{4 x ^{6}}

(1 - \frac{x}{3} = \frac{5 x}{3}) 3

π (\frac{250}{3} - 326)

What is expand-(-cos(θ)-λ)(1/2 sin^2(θ)) ?
The solution to expand-(-cos(θ)-λ)(1/2 sin^2(θ)) is (sin^2(θ)cos(θ)+sin^2(θ)λ)/2