What is ((asin(θ)-a)^2)/a+a ?

The solution to ((asin(θ)-a)^2)/a+a is 2a+asin^2(θ)-2asin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((asin(θ)-a)^2)/a+a

simplify

\frac{( a sin ( θ ) - a ) ^{2}}{a} + a

2 a + a sin^{2} (θ) - 2 a sin (θ)

Solution steps

\frac{( a sin ( θ ) - a ) ^{2}}{a} + a

Join

\frac{( a sin ( θ ) - a ) ^{2}}{a} + a : a (2 + sin^{2} (θ) - 2 sin (θ))

= a (2 + sin^{2} (θ) - 2 sin (θ))

Expand

a (2 + sin^{2} (θ) - 2 sin (θ)) : 2 a + a sin^{2} (θ) - 2 a sin (θ)

= 2 a + a sin^{2} (θ) - 2 a sin (θ)

\frac{( x - 4 ) ^{2}}{25}

\frac{( n + 2 ) ( - 11 n + 15 )}{2}

(1 + x^{2}) ln (x)

A (s (s - 3)^{2})

\frac{m ( g ^{2} - a ^{2} )}{( b + a ) ( b - a )}

What is ((asin(θ)-a)^2)/a+a ?
The solution to ((asin(θ)-a)^2)/a+a is 2a+asin^2(θ)-2asin(θ)