What is expand (32(2n+1)(n+1))/(3n^2) ?

The solution to expand (32(2n+1)(n+1))/(3n^2) is 64/3+(32)/n+(32)/(3n^2)

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expand (32(2n+1)(n+1))/(3n^2)

expand

\frac{32 ( 2 n + 1 ) ( n + 1 )}{3 n ^{2}}

\frac{64}{3} + \frac{32}{n} + \frac{32}{3 n ^{2}}

Solution steps

\frac{32 ( 2 n + 1 ) ( n + 1 )}{3 n ^{2}}

Expand

32 (2 n + 1) (n + 1) : 64 n^{2} + 96 n + 32

= \frac{64 n ^{2} + 96 n + 32}{3 n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 n ^{2} + 96 n + 32}{3 n ^{2}} = \frac{64 n ^{2}}{3 n ^{2}} + \frac{96 n}{3 n ^{2}} + \frac{32}{3 n ^{2}}

= \frac{64 n ^{2}}{3 n ^{2}} + \frac{96 n}{3 n ^{2}} + \frac{32}{3 n ^{2}}

Cancel

\frac{64 n ^{2}}{3 n ^{2}} : \frac{64}{3}

= \frac{64}{3} + \frac{96 n}{3 n ^{2}} + \frac{32}{3 n ^{2}}

Cancel

\frac{96 n}{3 n ^{2}} : \frac{32}{n}

= \frac{64}{3} + \frac{32}{n} + \frac{32}{3 n ^{2}}

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What is expand (32(2n+1)(n+1))/(3n^2) ?
The solution to expand (32(2n+1)(n+1))/(3n^2) is 64/3+(32)/n+(32)/(3n^2)