What are the solutions to the equation -12x^2-36x=0 ?

The solutions to the equation -12x^2-36x=0 are x=-3,x=0

Find the zeros of -12x^2-36x=0

The zeros of -12x^2-36x=0 are x=-3,x=0

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- 12 x^{2} - 36 x = 0

x = - 3, x = 0

Solution steps

- 12 x^{2} - 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

(- 36)^{2} - 4 (- 12) \cdot 0 = 36

x_{1, 2} = \frac{- ( - 36 ) \pm 36}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 36}{2 ( - 12 )}, x_{2} = \frac{- ( - 36 ) - 36}{2 ( - 12 )}

x = \frac{- ( - 36 ) + 36}{2 ( - 12 )} : - 3

x = \frac{- ( - 36 ) - 36}{2 ( - 12 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

6 x^{2} + 13 x = 5

9 x^{2} y^{2} - 3 x y^{2} - 90 y^{2}

(- 27)^{\frac{5}{3}}

\frac{3 + 6 i}{2 - 5 i}

0 = \frac{2}{5} x - 2

What are the solutions to the equation -12x^2-36x=0 ?
The solutions to the equation -12x^2-36x=0 are x=-3,x=0
Find the zeros of -12x^2-36x=0
The zeros of -12x^2-36x=0 are x=-3,x=0