What is expand (f\circ g)(x-5) ?

The solution to expand (f\circ g)(x-5) is \circ fgx-5\circ fg

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expand (f\circ g)(x-5)

expand

(f \circ g) (x - 5)

\circ f gx - 5 \circ f g

Solution steps

(f \circ g) (x - 5)

= (\circ f g) (x - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = (f \circ g), b = x, c = 5

= (f \circ g) x - (f \circ g) \cdot 5

= x (\circ f g) - 5 (\circ f g)

Remove parentheses:

(a) = a

= \circ f gx - 5 \circ f g

(7 + 22) (7 - 22)

\frac{( 3 - x ) ( 1 + x )}{( 4 - x )}

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\frac{x ^{2} + 2}{( x ^{2} + 3 ) ( x + 2 ) ^{2}}

(x^{\frac{3}{2}} - 2 y^{\frac{1}{2}}) (7 x^{\frac{1}{2}} + y^{\frac{3}{2}})

What is expand (f\circ g)(x-5) ?
The solution to expand (f\circ g)(x-5) is \circ fgx-5\circ fg