What is expand sin(θ)(-6,-5) ?

The solution to expand sin(θ)(-6,-5) is -6sin(θ),-5sin(θ)

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expand sin(θ)(-6,-5)

expand

sin (θ) (- 6, - 5)

- 6 sin (θ), - 5 sin (θ)

Solution steps

sin (θ) (- 6, - 5)

= (- 6, - 5) sin (θ)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (θ), b = - 6,, c = 5

= sin (θ) (- 6,) - sin (θ) \cdot 5

Apply minus-plus rules

+ (- a) = - a

= - 6 sin (θ), - 5 sin (θ)

(2 y + y^{2}) d x + (2 x + 2 x y) d y

\frac{\partial}{\partial t} ((x) (x^{2} + x t + t^{2} - 1))

y^{2} d x + (x y - x^{3}) d y

(10 x + 3) 5 - 2 x^{2} - 9 x

(1 + cot (θ))^{2}

What is expand sin(θ)(-6,-5) ?
The solution to expand sin(θ)(-6,-5) is -6sin(θ),-5sin(θ)