What is expand ((-1)^{n-1})/((n+4)^2) ?

The solution to expand ((-1)^{n-1})/((n+4)^2) is ((-1)^{n-1})/(n^2+8n+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((-1)^{n-1})/((n+4)^2)

expand

\frac{( - 1 ) ^{n - 1}}{( n + 4 ) ^{2}}

\frac{( - 1 ) ^{n - 1}}{n ^{2} + 8 n + 16}

Solution steps

\frac{( - 1 ) ^{n - 1}}{( n + 4 ) ^{2}}

(n + 4)^{2} = n^{2} + 8 n + 16

= \frac{( - 1 ) ^{n - 1}}{n ^{2} + 8 n + 16}

\frac{1}{4 - x ^{3}}

(y^{2} - 2 x e^{y}) d x

\frac{1}{( s - 1 ) s ^{2}}

7 (8 - 13)

What is expand ((-1)^{n-1})/((n+4)^2) ?
The solution to expand ((-1)^{n-1})/((n+4)^2) is ((-1)^{n-1})/(n^2+8n+16)