What is expand-e^{3x}(e^{-x}+1) ?

The solution to expand-e^{3x}(e^{-x}+1) is -e^{2x}-e^{3x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-e^{3x}(e^{-x}+1)

expand

- e^{3 x} (e^{- x} + 1)

- e^{2 x} - e^{3 x}

Solution steps

- e^{3 x} (e^{- x} + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = - e^{3 x}, b = e^{- x}, c = 1

= - e^{3 x} e^{- x} + (- e^{3 x}) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - e^{3 x} e^{- x} - 1 \cdot e^{3 x}

Simplify

- e^{3 x} e^{- x} - 1 \cdot e^{3 x} : - e^{2 x} - e^{3 x}

= - e^{2 x} - e^{3 x}

(1 + 2 π sin (2 π t))^{2}

\frac{\partial}{\partial x} ((z) (x^{2} + y^{2} + x y))

\frac{( 1 + a ) ^{n} + 2}{( 1 + a ) ^{2 n}}

\frac{2 x + 11}{( x - 2 ) ( x + 3 )}

(w - \frac{3}{2}) (w + \frac{7}{2})

What is expand-e^{3x}(e^{-x}+1) ?
The solution to expand-e^{3x}(e^{-x}+1) is -e^{2x}-e^{3x}