What is expand (e^{3+y}+5)+(e^{3+y}+6)y'(t) ?

The solution to expand (e^{3+y}+5)+(e^{3+y}+6)y'(t) is e^{3+y}+5+e^{3+y}y'(t)+6y'(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{3+y}+5)+(e^{3+y}+6)y'(t)

expand

(e^{3 + y} + 5) + (e^{3 + y} + 6) y^{'} (t)

e^{3 + y} + 5 + e^{3 + y} y' (t) + 6 y' (t)

Solution steps

(e^{3 + y} + 5) + (e^{3 + y} + 6) y^{'} (t)

Expand

y^{'} (t) (e^{3 + y} + 6) : e^{3 + y} y^{'} (t) + 6 y^{'} (t)

= (e^{3 + y} + 5) + e^{3 + y} y^{'} (t) + 6 y^{'} (t)

Remove parentheses:

(a) = a

= e^{3 + y} + 5 + e^{3 + y} y^{^{'}} (t) + 6 y^{^{'}} (t)

\frac{4 - 64}{20 + \frac{10000}{33 s} + 2 s}

3 (4 x + 15 y = 72)

(e^{3 x} - 1) \cdot (4 - x^{2})

\frac{( x ^{2} )}{( 6 + x ) ^{3}}

2 ((a + e) + (b + f))

What is expand (e^{3+y}+5)+(e^{3+y}+6)y'(t) ?
The solution to expand (e^{3+y}+5)+(e^{3+y}+6)y'(t) is e^{3+y}+5+e^{3+y}y'(t)+6y'(t)