What is expand (1/((2x+2h))-1/((2x)))/h ?

The solution to expand (1/((2x+2h))-1/((2x)))/h is -1/(2x^2+2xh)

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expand (1/((2x+2h))-1/((2x)))/h

expand

\frac{\frac{1}{( 2 x + 2 h )} - \frac{1}{( 2 x )}}{h}

- \frac{1}{2 x ^{2} + 2 x h}

Solution steps

\frac{\frac{1}{2 x + 2 h} - \frac{1}{2 x}}{h}

Join

\frac{1}{2 x + 2 h} - \frac{1}{2 x} : - \frac{h}{2 x ^{2} + 2 x h}

= \frac{- \frac{h}{2 x ^{2} + 2 x h}}{h}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{h}{2 x ^{2} + 2 x h}}{h}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{h}{2 x ^{2} + 2 x h}}{h} = \frac{h}{( 2 x ^{2} + 2 x h ) h}

= - \frac{h}{( 2 x ^{2} + 2 x h ) h}

Cancel the common factor:

h

= - \frac{1}{2 x ^{2} + 2 x h}

, (270 + 905) c m^{3}

(cos (θ) - i sin (θ))^{2}

1000 (1 + \frac{i}{12})^{12}

ln (x) (\frac{x ^{3}}{3} + 3 x) - \frac{1}{3} (\frac{x ^{3}}{3} + 9 x) + c

(1 - 3 i)^{16}

What is expand (1/((2x+2h))-1/((2x)))/h ?
The solution to expand (1/((2x+2h))-1/((2x)))/h is -1/(2x^2+2xh)