What is expand-((3-3x)^2)/2 ?

The solution to expand-((3-3x)^2)/2 is -(9x^2)/2+9x-9/2

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expand-((3-3x)^2)/2

expand

- \frac{( 3 - 3 x ) ^{2}}{2}

- \frac{9 x ^{2}}{2} + 9 x - \frac{9}{2}

Solution steps

- \frac{( 3 - 3 x ) ^{2}}{2}

(3 - 3 x)^{2} = 9 - 18 x + 9 x^{2}

= - \frac{9 x ^{2} - 18 x + 9}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 18 x + 9 x ^{2}}{2} = - (\frac{9}{2}) - (- \frac{18 x}{2}) - (\frac{9 x ^{2}}{2})

= - (\frac{9}{2}) - (- \frac{18 x}{2}) - (\frac{9 x ^{2}}{2})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{9}{2} + \frac{18 x}{2} - \frac{9 x ^{2}}{2}

Divide the numbers:

\frac{18}{2} = 9

= - \frac{9}{2} + 9 x - \frac{9 x ^{2}}{2}

Rewrite in standard form

= - \frac{9 x ^{2}}{2} + 9 x - \frac{9}{2}

\frac{d ^{3}}{d x ^{3}} ((y) (- sin (x) + 3 x^{2} - 8 x + 3))

(\frac{x + 4}{x ^{3} + 4 x})^{2}

3 x^{3} (- ln (x) + c)

2 (83 + 37)

q (20 - \frac{q}{30})

What is expand-((3-3x)^2)/2 ?
The solution to expand-((3-3x)^2)/2 is -(9x^2)/2+9x-9/2