What is -4((x+1)/4)>x-8(2/(3-x)) ?

The solution to -4((x+1)/4)>x-8(2/(3-x)) is x<3

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-4((x+1)/4)>x-8(2/(3-x))

- 4 (\frac{x + 1}{4}) > x - 8 (\frac{2}{3 - x})

x < 3

Interval Notation

(- \infty, 3)

Solution steps

- 4 \cdot \frac{x + 1}{4} > x - 8 \cdot \frac{2}{3 - x}

Rewrite in standard form

\frac{2 x ^{2} - 5 x + 13}{- x + 3} > 0

Identify the intervals

x < 3

- y^{2} + yz - x y

\frac{1}{2} 9

6 mn - 5 m^{2} n^{2} - 9 m n^{2} - 11 mn + 10 m n^{2} + 5 m^{2} n^{2}

3 x^{2} + x = - 2 x - 7

\frac{a + 2}{4} \leq \frac{a - 1}{3}

What is -4((x+1)/4)>x-8(2/(3-x)) ?
The solution to -4((x+1)/4)>x-8(2/(3-x)) is x<3