What is expand-((x+1)(x-3)(x-5))/(320) ?

The solution to expand-((x+1)(x-3)(x-5))/(320) is -(x^3)/(320)+(7x^2)/(320)-(7x)/(320)-3/64

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expand-((x+1)(x-3)(x-5))/(320)

expand

- \frac{( x + 1 ) ( x - 3 ) ( x - 5 )}{320}

- \frac{x ^{3}}{320} + \frac{7 x ^{2}}{320} - \frac{7 x}{320} - \frac{3}{64}

Solution steps

- \frac{( x + 1 ) ( x - 3 ) ( x - 5 )}{320}

Expand

(x + 1) (x - 3) (x - 5) : x^{3} - 7 x^{2} + 7 x + 15

= - \frac{x ^{3} - 7 x ^{2} + 7 x + 15}{320}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 7 x ^{2} + 7 x + 15}{320} = - (\frac{x ^{3}}{320}) - (- \frac{7 x ^{2}}{320}) - (\frac{7 x}{320}) - (\frac{15}{320})

= - (\frac{x ^{3}}{320}) - (- \frac{7 x ^{2}}{320}) - (\frac{7 x}{320}) - (\frac{15}{320})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{3}}{320} + \frac{7 x ^{2}}{320} - \frac{7 x}{320} - \frac{15}{320}

Cancel

\frac{15}{320} : \frac{3}{64}

= - \frac{x ^{3}}{320} + \frac{7 x ^{2}}{320} - \frac{7 x}{320} - \frac{3}{64}

A (- 3, - 6, - 3) y B (- 5, 4, - 7)

\frac{0.25 ( s + 4 )}{s ^{3} + 8 s ^{2} + 12 s + 10}

(x^{\frac{1}{3}} + 2)^{8}

\frac{0.00035 - x}{x ( - x + 0.001 )}

What is expand-((x+1)(x-3)(x-5))/(320) ?
The solution to expand-((x+1)(x-3)(x-5))/(320) is -(x^3)/(320)+(7x^2)/(320)-(7x)/(320)-3/64