What is (z^3+z^4)(7x+2/3) ?

The solution to (z^3+z^4)(7x+2/3) is ((z^3+z^4)(21x+2))/3

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simplify (z^3+z^4)(7x+2/3)

simplify

(z^{3} + z^{4}) (7 x + \frac{2}{3})

\frac{( z ^{3} + z ^{4} ) ( 21 x + 2 )}{3}

Solution steps

(z^{3} + z^{4}) (7 x + \frac{2}{3})

Join

7 x + \frac{2}{3} : \frac{21 x + 2}{3}

= (z^{3} + z^{4}) \frac{21 x + 2}{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( z ^{3} + z ^{4} ) ( 21 x + 2 )}{3}

- \frac{7 ( 2 x - 1 )}{( x - 5 ) ( x + 4 )}

\frac{2}{( s ^{2} + 1 ) ( s ^{2} + 2 )}

\frac{x ^{2} + y ^{2}}{2}

(x^{2} - 7 x + 10) + (- x + 2) i

2 (e + 1) (e - 1)

What is (z^3+z^4)(7x+2/3) ?
The solution to (z^3+z^4)(7x+2/3) is ((z^3+z^4)(21x+2))/3