What is expand-derivative of e^{-x(α+(βx/2)}) ?

The solution to expand-derivative of e^{-x(α+(βx/2)}) is -derivative of e^{-xα-(x^2β/2})

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expand-derivative of e^{-x(α+(βx/2)})

expand

- \frac{d}{d x} (e^{- x (α + \frac{β x}{2})})

- \frac{d}{d x} (e^{- xα - \frac{x ^{2} β}{2}})

Solution steps

- \frac{d}{d x} (e^{- x (α + \frac{β x}{2})})

Expand

- x (α + \frac{β x}{2}) : - xα - \frac{x ^{2} β}{2}

= - \frac{d}{d x} (e^{- \frac{x ^{2} β}{2} - xα})

(14 + x^{2} + y^{2} + z^{2}) 6

f (x) (2 - 3 x) sin (x)

9 - x^{2} (x + 1)

7 (7 + x 21)

What is expand-derivative of e^{-x(α+(βx/2)}) ?
The solution to expand-derivative of e^{-x(α+(βx/2)}) is -derivative of e^{-xα-(x^2β/2})