What is the answer to 45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)] ?

The answer to 45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)] is y=-81/11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)]

45 - [4 - 2 y - 4 (y + 7)] = - 4 (1 + 3 y) - [4 - 3 (y + 2) - 2 (2 y - 5)]

y = - \frac{81}{11}

Decimal Notation

y = - 7.36363 \dots

Solution steps

45 - [4 - 2 y - 4 (y + 7)] = - 4 (1 + 3 y) - [4 - 3 (y + 2) - 2 (2 y - 5)]

Expand

45 - (4 - 2 y - 4 (y + 7)) : 6 y + 69

Expand

- 4 (1 + 3 y) - (4 - 3 (y + 2) - 2 (2 y - 5)) : - 5 y - 12

6 y + 69 = - 5 y - 12

Move

69

to the right side

6 y = - 5 y - 81

Move

5 y

to the left side

11 y = - 81

Divide both sides by

11

y = - \frac{81}{11}

- \frac{1}{2} (- 12 y + 16) = 5 y - 9

a^{2} \leq 1

8 x - (2 - 3 x) = 18

\frac{4 - 4}{( 4 ) ^{2} + ( 500 ) ^{2}}

lo g_{2} (10) = t

What is the answer to 45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)] ?
The answer to 45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)] is y=-81/11
Solve for y: 45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)]
The solution is y=-81/11