What is expand solve(x-2)(x+3)(x^2-4x-1) ?

The solution to expand solve(x-2)(x+3)(x^2-4x-1) is elsovx^4-3elsovx^3-11elsovx^2+23elsovx+6elsov

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand solve(x-2)(x+3)(x^2-4x-1)

expand

so l v e (x - 2) (x + 3) (x^{2} - 4 x - 1)

e l so v x^{4} - 3 e l so v x^{3} - 11 e l so v x^{2} + 23 e l so vx + 6 e l so v

Solution steps

so l v e (x - 2) (x + 3) (x^{2} - 4 x - 1)

= e l so v (x - 2) (x + 3) (x^{2} - 4 x - 1)

Expand

(x - 2) (x + 3) : x^{2} + x - 6

= so l v e (x^{2} + x - 6) (x^{2} - 4 x - 1)

Expand

(x^{2} + x - 6) (x^{2} - 4 x - 1) : x^{4} - 3 x^{3} - 11 x^{2} + 23 x + 6

= so l v e (x^{4} - 3 x^{3} - 11 x^{2} + 23 x + 6)

Expand

so l v e (x^{4} - 3 x^{3} - 11 x^{2} + 23 x + 6) : e l so v x^{4} - 3 e l so v x^{3} - 11 e l so v x^{2} + 23 e l so vx + 6 e l so v

= e l so v x^{4} - 3 e l so v x^{3} - 11 e l so v x^{2} + 23 e l so vx + 6 e l so v

(t - 3) e (- s t)

- \frac{1}{8} (x - 1)^{2}

(v + 6) (d v + y d y)

(- e^{t} sin (t) + cos (t) e^{t})^{2}

\frac{2 s ^{2} + 1}{s ( s + 1 ) ^{2}}

What is expand solve(x-2)(x+3)(x^2-4x-1) ?
The solution to expand solve(x-2)(x+3)(x^2-4x-1) is elsovx^4-3elsovx^3-11elsovx^2+23elsovx+6elsov