What is expand (f\circ g)(x+2) ?

The solution to expand (f\circ g)(x+2) is \circ fgx+2\circ fg

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expand (f\circ g)(x+2)

expand

(f \circ g) (x + 2)

\circ f gx + 2 \circ f g

Solution steps

(f \circ g) (x + 2)

= (\circ f g) (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = (f \circ g), b = x, c = 2

= (f \circ g) x + (f \circ g) \cdot 2

= x (\circ f g) + 2 (\circ f g)

Remove parentheses:

(a) = a

= \circ f gx + 2 \circ f g

\frac{2}{3} + \frac{1}{5}

\frac{( ( 1 + 16 π ^{2} ) ^{\frac{3}{2}} - 1 ) 2}{3}

\frac{( - t ^{2} + 20 t - 62 ) ^{2}}{4}

, a (1 - a - (\frac{( 1 - a - d )}{2})) - c a - i

8 (\frac{x}{4} - \frac{3}{2})

What is expand (f\circ g)(x+2) ?
The solution to expand (f\circ g)(x+2) is \circ fgx+2\circ fg