What is expand ((x^2+4x+3)(x+1))/(36) ?

The solution to expand ((x^2+4x+3)(x+1))/(36) is (x^3)/(36)+(5x^2)/(36)+(7x)/(36)+1/12

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expand ((x^2+4x+3)(x+1))/(36)

expand

\frac{( x ^{2} + 4 x + 3 ) ( x + 1 )}{36}

\frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{1}{12}

Solution steps

\frac{( x ^{2} + 4 x + 3 ) ( x + 1 )}{36}

Expand

(x^{2} + 4 x + 3) (x + 1) : x^{3} + 5 x^{2} + 7 x + 3

= \frac{x ^{3} + 5 x ^{2} + 7 x + 3}{36}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 5 x ^{2} + 7 x + 3}{36} = \frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{3}{36}

= \frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{3}{36}

Cancel

\frac{3}{36} : \frac{1}{12}

= \frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{1}{12}

f (x) 3 t + 4 (g (x, t) = - 3)

\frac{1}{( 1 - 5 x ) ^{- \frac{1}{4}}}

(sin (a) + cos (b)) (sin (b) + cos (a))

p^{\frac{1}{4}} (p^{\frac{3}{4}} + 3 p^{\frac{7}{4}})

A (- 2, 22) B (13, - 19)

What is expand ((x^2+4x+3)(x+1))/(36) ?
The solution to expand ((x^2+4x+3)(x+1))/(36) is (x^3)/(36)+(5x^2)/(36)+(7x)/(36)+1/12