What is expand (xsin(θ)-ysin(θ))^2 ?

The solution to expand (xsin(θ)-ysin(θ))^2 is x^2sin^2(θ)-2xysin^2(θ)+y^2sin^2(θ)

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expand (xsin(θ)-ysin(θ))^2

expand

(x sin (θ) - y sin (θ))^{2}

x^{2} sin^{2} (θ) - 2 x y sin^{2} (θ) + y^{2} sin^{2} (θ)

Solution steps

(x sin (θ) - y sin (θ))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x sin (θ) - y sin (θ))^{2} = (x sin (θ))^{2} - 2 x sin (θ) y sin (θ) + (y sin (θ))^{2}

= (x sin (θ))^{2} - 2 x sin (θ) y sin (θ) + (y sin (θ))^{2}

Simplify

(x sin (θ))^{2} - 2 x sin (θ) y sin (θ) + (y sin (θ))^{2} : x^{2} sin^{2} (θ) - 2 x y sin^{2} (θ) + y^{2} sin^{2} (θ)

= x^{2} sin^{2} (θ) - 2 x y sin^{2} (θ) + y^{2} sin^{2} (θ)

(6 t^{2} - 2 t + 13 - 3 t) \cdot (- 3, - 1)

x (x + 2 x + 1)

2 (sin (x) + cos (x) = sec (x))

20 cos (x) (sin (x) + 1)

p (- 2, 12) y q (5, - 9)

What is expand (xsin(θ)-ysin(θ))^2 ?
The solution to expand (xsin(θ)-ysin(θ))^2 is x^2sin^2(θ)-2xysin^2(θ)+y^2sin^2(θ)