What is expand (20G(C)-80C=4,6)(100G(C)-160C=140) ?

The solution to expand (20G(C)-80C=4,6)(100G(C)-160C=140) is 2000G(C)^2-3200CG(C)=140

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expand (20G(C)-80C=4,6)(100G(C)-160C=140)

expand

(20 G (C) - 80 C = 4, 6) (100 G (C) - 160 C = 140)

2000 G (C)^{2} - 3200 CG (C) = 140

Solution steps

(20 G (C) - 80 C = 4, 6) (100 G (C) - 160 C = 140)

= (20 G (C) - 80 \cdot 4 \cdot 6 =, C) (100 G (C) - 160 \cdot 140 = C)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 20 G (C), b = - 80 C = 4, 6, c = 100 G (C), d = - 160 C = 140

= 20 G (C) \cdot 100 G (C) + 20 G (C) (- 160 C = 140) + (- 80 C = 4, 6) \cdot 100 G (C) + (- 80 C = 4, 6) (- 160 C = 140)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

20 \cdot 100 G (C) G (C) - 20 \cdot 160 CG (C) = 140 - 80 C = 4, 6 \cdot 100 G (C) + 80 C = 4, 6 \cdot 160 C = 140

Expand

20 \cdot 100 G (C) G (C) - 20 \cdot 160 CG (C) : 2000 G (C)^{2} - 3200 CG (C)

2000 G (C)^{2} - 3200 CG (C) = 140

(\frac{1}{2} \cdot x - \frac{1}{2})^{10}

x^{\frac{3}{5}} (x - 8)

\frac{x}{( 0.1111 - 2 x ) ^{2}}

lo g_{8} (64)

\frac{8 x}{( x + 4 ) ( x - 5 )}

What is expand (20G(C)-80C=4,6)(100G(C)-160C=140) ?
The solution to expand (20G(C)-80C=4,6)(100G(C)-160C=140) is 2000G(C)^2-3200CG(C)=140