What is (4-b/c)(b/c+4) ?

The solution to (4-b/c)(b/c+4) is ((4c-b)(4c+b))/(c^2)

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simplify (4-b/c)(b/c+4)

simplify

(4 - \frac{b}{c}) (\frac{b}{c} + 4)

\frac{( 4 c - b ) ( 4 c + b )}{c ^{2}}

Solution steps

(4 - \frac{b}{c}) (\frac{b}{c} + 4)

Join

4 - \frac{b}{c} : \frac{4 c - b}{c}

= \frac{4 c - b}{c} (\frac{b}{c} + 4)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 4 c - b ) ( \frac{b}{c} + 4 )}{c}

Simplify

(4 c - b) (\frac{b}{c} + 4) : \frac{( 4 c - b ) ( 4 c + b )}{c}

= \frac{\frac{( 4 c - b ) ( 4 c + b )}{c}}{c}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 4 c - b ) ( 4 c + b )}{cc}

Apply exponent rule:

aa = a^{2}

cc = c^{2}

= \frac{( 4 c - b ) ( 4 c + b )}{c ^{2}}

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