What is expand 3/((x^2+9)(x-12)) ?

The solution to expand 3/((x^2+9)(x-12)) is 3/(x^3-12x^2+9x-108)

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expand 3/((x^2+9)(x-12))

expand

\frac{3}{( x ^{2} + 9 ) ( x - 12 )}

\frac{3}{x ^{3} - 12 x ^{2} + 9 x - 108}

Solution steps

\frac{3}{( x ^{2} + 9 ) ( x - 12 )}

Expand

(x^{2} + 9) (x - 12) : x^{3} - 12 x^{2} + 9 x - 108

= \frac{3}{x ^{3} - 12 x ^{2} + 9 x - 108}

\frac{d}{d u} ((x) (x + 1))

2 (2 x - 4)

440 2 + 2 (2 - 2)

(f x + e) \cdot (x^{2} - x + 1) \cdot (x - 1)

- sin (x) (sin (x) + 1) - cos^{2} (x)

What is expand 3/((x^2+9)(x-12)) ?
The solution to expand 3/((x^2+9)(x-12)) is 3/(x^3-12x^2+9x-108)