What is expand ((x+2)(x-3))/(4(3x-1)(x+1)) ?

The solution to expand ((x+2)(x-3))/(4(3x-1)(x+1)) is (x^2-x-6)/(12x^2+8x-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x+2)(x-3))/(4(3x-1)(x+1))

expand

\frac{( x + 2 ) ( x - 3 )}{4 ( 3 x - 1 ) ( x + 1 )}

\frac{x ^{2} - x - 6}{12 x ^{2} + 8 x - 4}

Solution steps

\frac{( x + 2 ) ( x - 3 )}{4 ( 3 x - 1 ) ( x + 1 )}

Expand

4 (3 x - 1) (x + 1) : 12 x^{2} + 8 x - 4

= \frac{( x + 2 ) ( x - 3 )}{12 x ^{2} + 8 x - 4}

Expand

(x + 2) (x - 3) : x^{2} - x - 6

= \frac{x ^{2} - x - 6}{12 x ^{2} + 8 x - 4}

\frac{\partial}{\partial y} ((z) (- 3 x + 5 y + z))

(n + 1) (\frac{n}{2}) (n)

\frac{\frac{1}{5}}{y - 3} - \frac{\frac{1}{5}}{y + 2}

\frac{d}{d x} ((z (x, y)) (6 x^{5} + 4 y^{3} + 4 y))

What is expand ((x+2)(x-3))/(4(3x-1)(x+1)) ?
The solution to expand ((x+2)(x-3))/(4(3x-1)(x+1)) is (x^2-x-6)/(12x^2+8x-4)