What is expand ((3x+4)(x-9))/((x-2)(x+2)) ?

The solution to expand ((3x+4)(x-9))/((x-2)(x+2)) is (3x^2-23x-36)/(x^2-4)

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expand ((3x+4)(x-9))/((x-2)(x+2))

expand

\frac{( 3 x + 4 ) ( x - 9 )}{( x - 2 ) ( x + 2 )}

\frac{3 x ^{2} - 23 x - 36}{x ^{2} - 4}

Solution steps

\frac{( 3 x + 4 ) ( x - 9 )}{( x - 2 ) ( x + 2 )}

Expand

(x - 2) (x + 2) : x^{2} - 4

= \frac{( 3 x + 4 ) ( x - 9 )}{x ^{2} - 4}

Expand

(3 x + 4) (x - 9) : 3 x^{2} - 23 x - 36

= \frac{3 x ^{2} - 23 x - 36}{x ^{2} - 4}

\frac{1}{2} (x - 3)^{2} (x + 1)^{3}

\frac{4}{( s + 2 ) ^{2}}

\frac{( e ^{- s} + s ^{2} + s + 10 )}{( s + 4 ) ( s - 2 ) ( s - 1 )}

\frac{s ^{2} + 9 s + 10}{( s + 1 ) ( s ^{2} + 5 s + 6 )}

What is expand ((3x+4)(x-9))/((x-2)(x+2)) ?
The solution to expand ((3x+4)(x-9))/((x-2)(x+2)) is (3x^2-23x-36)/(x^2-4)