What is 1+(3kc)/((s+3)(s+1)(0.5s+1)) ?

The solution to 1+(3kc)/((s+3)(s+1)(0.5s+1)) is (0.5s^3+3s^2+5.5s+3+3kc)/((s+3)(s+1)(0.5s+1))

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simplify 1+(3kc)/((s+3)(s+1)(0.5s+1))

simplify

1 + \frac{3 k c}{( s + 3 ) ( s + 1 ) ( 0.5 s + 1 )}

\frac{0.5 s ^{3} + 3 s ^{2} + 5.5 s + 3 + 3 k c}{( s + 3 ) ( s + 1 ) ( 0.5 s + 1 )}

Solution steps

1 + \frac{3 k c}{( s + 3 ) ( s + 1 ) ( 0.5 s + 1 )}

Apply the fraction rule:

1 + \frac{b}{c} = \frac{c + b}{c}

= \frac{( s + 3 ) ( s + 1 ) ( 0.5 s + 1 ) + 3 k c}{( s + 3 ) ( s + 1 ) ( 0.5 s + 1 )}

Simplify

(s + 3) (s + 1) (0.5 s + 1) + 3 k c : 0.5 s^{3} + 3 s^{2} + 5.5 s + 3 + 3 k c

= \frac{0.5 s ^{3} + 3 s ^{2} + 5.5 s + 3 + 3 k c}{( s + 3 ) ( s + 1 ) ( 0.5 s + 1 )}

142 + \frac{142 ( x - 142 )}{284}

14 - (27)

\frac{( 3 - x ) ( 10 + 11 x )}{( 3 - 11 x ) ( 8 + 11 x )}

(x^{2} - 2 y^{2}) \times e^{x - y}

(2 x - 1)^{\frac{1}{2}} (2 x^{2} + 1)

What is 1+(3kc)/((s+3)(s+1)(0.5s+1)) ?
The solution to 1+(3kc)/((s+3)(s+1)(0.5s+1)) is (0.5s^3+3s^2+5.5s+3+3kc)/((s+3)(s+1)(0.5s+1))