What are the solutions to the equation solvefor y,4x^2+y^2-8x=-4 ?

The solutions to the equation solvefor y,4x^2+y^2-8x=-4 are y=2sqrt(-1-x^2+2x),y=-2sqrt(-1-x^2+2x)

Find the zeros of solvefor y,4x^2+y^2-8x=-4

The zeros of solvefor y,4x^2+y^2-8x=-4 are y=2sqrt(-1-x^2+2x),y=-2sqrt(-1-x^2+2x)

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solve for

y, 4 x^{2} + y^{2} - 8 x = - 4

y = 2 - 1 - x^{2} + 2 x, y = - 2 - 1 - x^{2} + 2 x

Solution steps

4 x^{2} + y^{2} - 8 x = - 4

Move

4 x^{2}

to the right side

y^{2} - 8 x = - 4 - 4 x^{2}

Move

8 x

to the right side

y^{2} = - 4 - 4 x^{2} + 8 x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4 - 4 x^{2} + 8 x, y = - - 4 - 4 x^{2} + 8 x

Simplify

- 4 - 4 x^{2} + 8 x : 2 - 1 - x^{2} + 2 x

Simplify

- - 4 - 4 x^{2} + 8 x : - 2 - 1 - x^{2} + 2 x

y = 2 - 1 - x^{2} + 2 x, y = - 2 - 1 - x^{2} + 2 x

(1 + i)^{3}

\frac{- 15 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

∣ 3 j - 1 ∣ + 6 \geq 0

∣ x - 2 ∣ = 3 x + 10

lo g_{14} (25)

What are the solutions to the equation solvefor y,4x^2+y^2-8x=-4 ?
The solutions to the equation solvefor y,4x^2+y^2-8x=-4 are y=2sqrt(-1-x^2+2x),y=-2sqrt(-1-x^2+2x)
Find the zeros of solvefor y,4x^2+y^2-8x=-4
The zeros of solvefor y,4x^2+y^2-8x=-4 are y=2sqrt(-1-x^2+2x),y=-2sqrt(-1-x^2+2x)