What is (-15r^6s^7t^4)/(3r^2s^9t^7) ?

The solution to (-15r^6s^7t^4)/(3r^2s^9t^7) is -(5r^4)/(s^2t^3)

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simplify (-15r^6s^7t^4)/(3r^2s^9t^7)

simplify

\frac{- 15 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

- \frac{5 r ^{4}}{s ^{2} t ^{3}}

Solution steps

\frac{- 15 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

Factor the number:

15 = 3 \cdot 5

= \frac{- 3 \cdot 5 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

Cancel the common factor:

3

= \frac{- 5 r ^{6} s ^{7} t ^{4}}{r ^{2} s ^{9} t ^{7}}

Simplify

\frac{r ^{6}}{r ^{2}} : r^{4}

= \frac{- 5 r ^{4} s ^{7} t ^{4}}{s ^{9} t ^{7}}

Simplify

\frac{s ^{7}}{s ^{9}} : \frac{1}{s ^{2}}

= \frac{- 5 r ^{4} t ^{4}}{s ^{2} t ^{7}}

Simplify

\frac{t ^{4}}{t ^{7}} : \frac{1}{t ^{3}}

= \frac{- 5 r ^{4}}{s ^{2} t ^{3}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{5 r ^{4}}{s ^{2} t ^{3}}

∣ 3 j - 1 ∣ + 6 \geq 0

∣ x - 2 ∣ = 3 x + 10

lo g_{14} (25)

- 3 x^{2} + 27

\frac{x - 2}{3} - \frac{x + 1}{12} = \frac{4 x - 3}{12}

What is (-15r^6s^7t^4)/(3r^2s^9t^7) ?
The solution to (-15r^6s^7t^4)/(3r^2s^9t^7) is -(5r^4)/(s^2t^3)