What is (\partial)/(\partial x)((z)(2x^2+y^2)) ?

The answer to (\partial)/(\partial x)((z)(2x^2+y^2)) is 4zx

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(\partial)/(\partial x)((z)(2x^2+y^2))

\frac{\partial}{\partial x} ((z) (2 x^{2} + y^{2}))

4 z x

Solution steps

\frac{\partial}{\partial x} ((z) (2 x^{2} + y^{2}))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (2 x^{2} + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (y^{2}))

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y^{2}) = 0

= z (4 x + 0)

Simplify

= 4 z x

A (- 4, - 7)

(2 x + \frac{1}{x})^{5}

(5 x - 10) (3 - x)

\frac{20 ( s + 1 )}{s ( 5 s ^{2} + 6 s + 2 )}

(- x^{2} + 0.5 x + 5) d x

What is (\partial)/(\partial x)((z)(2x^2+y^2)) ?
The answer to (\partial)/(\partial x)((z)(2x^2+y^2)) is 4zx