What is expand (a+5)-b/(b-4)+(2(b+3))/a ?

The solution to expand (a+5)-b/(b-4)+(2(b+3))/a is a+5-b/(b-4)+(2b)/a+6/a

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expand (a+5)-b/(b-4)+(2(b+3))/a

expand

(a + 5) - \frac{b}{b - 4} + \frac{2 ( b + 3 )}{a}

a + 5 - \frac{b}{b - 4} + \frac{2 b}{a} + \frac{6}{a}

Solution steps

(a + 5) - \frac{b}{b - 4} + \frac{2 ( b + 3 )}{a}

Remove parentheses:

(a) = a

= a + 5 - \frac{b}{b - 4} + \frac{2 ( b + 3 )}{a}

Expand

2 (b + 3) : 2 b + 6

= a + 5 - \frac{b}{b - 4} + \frac{2 b + 6}{a}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 b + 6}{a} = \frac{2 b}{a} + \frac{6}{a}

= a + 5 - \frac{b}{b - 4} + \frac{2 b}{a} + \frac{6}{a}

(\frac{a}{6} + \frac{b ^{3}}{5}) (\frac{a}{6} - \frac{b ^{3}}{5})

\frac{2 a}{5 ( a - b )}

- \frac{x ( 3 x - 4 )}{2}

e^{x} \cdot (e^{x} + 9)^{5}

What is expand (a+5)-b/(b-4)+(2(b+3))/a ?
The solution to expand (a+5)-b/(b-4)+(2(b+3))/a is a+5-b/(b-4)+(2b)/a+6/a