What is expand (4y^2-1/(8y^3))^2 ?

The solution to expand (4y^2-1/(8y^3))^2 is (1024y^{10}-64y^5+1)/(64y^6)

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expand (4y^2-1/(8y^3))^2

expand

(4 y^{2} - \frac{1}{8 y ^{3}})^{2}

\frac{1024 y ^{10} - 64 y ^{5} + 1}{64 y ^{6}}

Solution steps

(4 y^{2} - \frac{1}{8 y ^{3}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(4 y^{2} - \frac{1}{8 y ^{3}})^{2} = (4 y^{2})^{2} - 2 \cdot 4 y^{2} \frac{1}{8 y ^{3}} + (\frac{1}{8 y ^{3}})^{2}

= (4 y^{2})^{2} - 2 \cdot 4 y^{2} \frac{1}{8 y ^{3}} + (\frac{1}{8 y ^{3}})^{2}

Simplify

(4 y^{2})^{2} - 2 \cdot 4 y^{2} \frac{1}{8 y ^{3}} + (\frac{1}{8 y ^{3}})^{2} : \frac{1024 y ^{10} - 64 y ^{5} + 1}{64 y ^{6}}

= \frac{1024 y ^{10} - 64 y ^{5} + 1}{64 y ^{6}}

\frac{d}{d p} ((t) (p + n^{2} a))

(f \circ g) 3 (3 x^{2} + 7) + 5 (3 x^{2} + 7)

x^{2} - \frac{5}{3} x

\frac{2 ( x - 1 ) ^{2} ( x - 3 )}{( x + 2 ) ( x + 7 )}

f^{'} (x) (45 - p (x))

What is expand (4y^2-1/(8y^3))^2 ?
The solution to expand (4y^2-1/(8y^3))^2 is (1024y^{10}-64y^5+1)/(64y^6)